KPSC Staff Nurse - 2018
Biochemistry and Nutrition
Easy

The designation of an orbital with $\mathbf{n}=4$ and $\mathbf{l}=2$ is?

Appeared in: KPSC Staff Nurse - 2018

Explanation

  • The principal quantum number (n) indicates the main energy level, which is given as 4.
  • The azimuthal quantum number (l) defines the subshell (orbital shape). An l value of 2 specifically corresponds to the 'd' subshell.
  • Combining the principal number (4) and the subshell letter (d) gives the designation 4d.

Why Other Options Were Wrong

  • Option B: The 4s designation corresponds to an azimuthal quantum number (l) of 0, not 2.
  • Option C: The 4p designation corresponds to an azimuthal quantum number (l) of 1, not 2.
  • Option D: The 4f designation corresponds to an azimuthal quantum number (l) of 3, not 2.

Related Visual

Visual explanation — Related Visual
Clinical Relevance
  • Nursing practice connection: This is primarily an exam-oriented knowledge point with limited direct bedside application, so retain Quantum Numbers and Atomic Orbital Designation as background academic context rather than a clinical decision trigger.
  • Understanding atomic structure is a fundamental prerequisite for studying biochemistry and pharmacology, as the electronic configuration of atoms dictates their chemical bonding and reactivity.
  • The principles of electron orbitals are essential for interpreting advanced imaging techniques like Magnetic Resonance Imaging (MRI), which relies on the quantum mechanical properties of atomic nuclei.
  • What if? If the question asked for n=3 and l=1, the answer would be 3p, as n=3 is the third energy level and l=1 corresponds to the 'p' subshell.
How to Approach the Question
  • First, identify the given quantum numbers in the question: n (principal) and l (azimuthal).
  • Recall that 'n' gives the number part of the orbital designation.
  • Recall the letter codes for the 'l' values: l=0 is 's', l=1 is 'p', l=2 is 'd', and l=3 is 'f'.
  • Match the given 'l' value (l=2) to its corresponding letter ('d').
  • Combine the number from 'n' (4) and the letter from 'l' ('d') to form the final orbital designation: 4d.
Concept Tested & Keywords
  • Concept Tested: Quantum Numbers and Atomic Orbital Designation
  • Stem keywords: designation, orbital, n=4, l=2
  • Lead-in keywords: BEST, MOST RELEVANT CLUE
  • Negative lead-in flag: false

Question ID

QpdabnIZGoo8mPLHHByePS

Practise the full KPSC Staff Nurse - 2018

Attempt every question from this paper in a timed mock, then review the full solution for each one.