RRB Nsg. Superintendent-2026 (Shift -1st)
General Knowledge
Medium

A stone is thrown vertically downwards with a speed of 5 m/s from the top of a tower. What will be its velocity after 2 seconds? (Take g = 10 m/s²)

Appeared in: RRB Nsg. Superintendent-2026 (Shift -1st)

Explanation

  • The problem involves an object moving with constant acceleration (gravity), so the kinematic equations of motion apply.
  • The first equation of motion, v = u + at, relates final velocity (v), initial velocity (u), acceleration (a), and time (t).
  • The given values are: initial velocity (u) = 5 m/s, acceleration (a) = g = 10 m/s², and time (t) = 2 s.
  • Since the motion is downwards, both initial velocity and acceleration due to gravity are in the same direction and can be treated as positive values.
  • Substituting the values into the formula gives: v = 5 + (10 × 2) = 5 + 20 = 25 m/s.

Why Other Options Were Wrong

  • Option A: This result is calculated by assuming the initial velocity (u) is 0 m/s (v = 0 + 10 × 2). However, the problem states the stone was thrown with an initial speed of 5 m/s.
  • Option C: This result is obtained by using a time (t) of 1 second instead of 2 seconds (v = 5 + 10 × 1).
  • Option D: This result does not follow from the given values. It could arise from a calculation error or assuming an incorrect initial velocity, such as 10 m/s (v = 10 + 10 × 2).

Related Visual

Visual explanation — Related Visual
  • Visual 1: Diagram - A diagram showing a stone being thrown downwards from a tower. Vectors should illustrate the initial velocity (u), the constant downward acceleration due to gravity (g), and the final velocity (v) after time (t). This helps visualize the vector quantities.
  • Visual 2: Infographic - A chart summarizing the three main equations of motion for constant linear acceleration, with the equation v = u + at highlighted for this specific problem.
Clinical Relevance
  • Nursing practice connection: This is primarily an exam-oriented knowledge point with limited direct bedside application, so retain Equations of motion for an object under constant acceleration (gravity) as background academic context rather than a clinical decision trigger.
  • This question tests fundamental physics principles (kinematics), which are often included in the general science or aptitude sections of nursing entrance examinations.
  • While not a direct nursing skill, understanding concepts like velocity and acceleration provides a foundational knowledge for biomechanics, which is relevant to understanding trauma from falls, accidents, and other injuries.
  • What if? If the stone were thrown upwards with a speed of 5 m/s, the initial velocity would be in the opposite direction to gravity. Taking the downward direction as positive, the initial velocity would be u = -5 m/s. The velocity after 2 seconds would be v = -5 + (10 × 2) = 15 m/s, indicating it is moving downwards at 15 m/s.
How to Approach the Question
  • First, identify and list all the known quantities provided in the problem: initial velocity (u), acceleration (a), and time (t).
  • Note the direction of motion. The stone is thrown 'vertically downwards', so the initial velocity (u = 5 m/s) and the acceleration due to gravity (g = 10 m/s²) are in the same direction.
  • Select the appropriate kinematic equation that connects the unknown variable (final velocity, v) with the known variables. The correct equation here is v = u + at.
  • Substitute the known values into the chosen equation: v = 5 + (10 × 2).
  • Perform the mathematical calculation to solve for the final velocity, v.
  • Finally, compare your calculated result with the given options to select the correct answer.
Concept Tested & Keywords
  • Concept Tested: Equations of motion for an object under constant acceleration (gravity).
  • Stem keywords: stone, vertically downwards, speed, 5 m/s, tower, velocity, 2 seconds, g = 10 m/s²
  • Lead-in keywords: What will be

Question ID

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