DSSSB -28 August 2019 (Shift-2)
Non Nursing Subjects
Hard

What is the least number that should be added to 2480 so that the sum is exactly divisible by 3, 4, 5 and 6?

Appeared in: DSSSB -28 August 2019 (Shift-2)

Explanation

  • The core concept is that for a number to be divisible by a set of numbers, it must be divisible by their Least Common Multiple (LCM).
  • First, calculate the LCM of 3, 4, 5, and 6, which is 60.
  • Next, divide the given number, 2480, by the LCM (60). This gives a remainder of 20.
  • The number that needs to be added is the difference between the LCM and the remainder (60 - 20 = 40).
  • Adding 40 to 2480 gives 2520, which is the next multiple of 60 after 2480.

Why Other Options Were Wrong

  • Option B: Adding 60 (the LCM itself) results in 2540. When 2540 is divided by 60, it leaves a remainder of 20, so it is not exactly divisible.
  • Option C: 20 is the remainder when 2480 is divided by the LCM (60). Adding the remainder (2480 + 20 = 2500) does not make the sum divisible by 60 (2500 ÷ 60 leaves a remainder of 40).
  • Option D: Adding 50 to 2480 gives 2530. When 2530 is divided by 60, it leaves a remainder of 10, so it is not exactly divisible.

Related Visual

Visual explanation — Related Visual
Clinical Relevance
  • Nursing practice connection: This is primarily an exam-oriented knowledge point with limited direct bedside application, so retain Finding the least number to be added to a given number to make it exactly divisible by a set of other numbers as background academic context rather than a clinical decision trigger.
  • This is a general aptitude and reasoning question, not a clinical one.
  • This type of problem tests foundational mathematical skills, specifically number theory involving LCM and division, which are essential for logical reasoning and problem-solving in various fields.
  • What if the question asked for the least number to be subtracted? In that case, the answer would be the remainder itself, which is 20.
How to Approach the Question
  • Identify the core task: Find the smallest number to add to 2480 to make it divisible by 3, 4, 5, and 6.
  • Recognize that for a number to be divisible by several other numbers, it must be divisible by their Least Common Multiple (LCM).
  • Calculate the LCM of the divisors (3, 4, 5, 6).
  • Divide the given number (2480) by the calculated LCM and find the remainder.
  • The number to be added is the difference between the LCM and the remainder. This will bring the original number up to the next exact multiple of the LCM.
  • Verify your answer by adding the number to 2480 and checking if the sum is divisible by the LCM.
Concept Tested & Keywords
  • Concept Tested: Finding the least number to be added to a given number to make it exactly divisible by a set of other numbers.
  • Stem keywords: least number, added to 2480, exactly divisible, 3, 4, 5 and 6
  • Lead-in keywords: What is

Question ID

QAFCga6OKkGe2CKtOqLg0e

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