The day of the week is found by calculating the total number of 'odd days' from a reference point (Year 0) to the day before the target date.
An odd day is a day remaining after counting the complete weeks in a given period. An ordinary year has 1 odd day (365/7 = 52 weeks + 1 day), and a leap year has 2 odd days (366/7 = 52 weeks + 2 days).
The calculation for the 1999 years up to December 31, 1999, is broken down into centuries and remaining years: 1600 years (0 odd days) + 300 years (1 odd day) + 99 years (4 odd days).
The total number of odd days up to December 31, 1999, is 0 + 1 + 4 = 5.
Using the standard day codes (0=Sunday, 1=Monday, ..., 5=Friday, 6=Saturday), 5 odd days means December 31, 1999, was a Friday.
Therefore, the next day, January 1, 2000, must be a Saturday.
Why Other Options Were Wrong
Option A: Friday corresponds to 5 odd days. This was the day for December 31, 1999, the day before the date in question. This is a common off-by-one error where the calculation stops a day too early.
Option C: Sunday corresponds to 0 odd days. The calculation resulted in 5 odd days for Dec 31, 1999, and thus 6 odd days (Saturday) for Jan 1, 2000. A result of Sunday would require a different number of odd days.
Option D: Monday corresponds to 1 odd day. The calculation resulted in 5 odd days for Dec 31, 1999, and thus 6 odd days (Saturday) for Jan 1, 2000. A result of Monday is incorrect.
Related Visual
Clinical Relevance
Nursing practice connection: This is primarily an exam-oriented knowledge point with limited direct bedside application, so retain Calculating the day of the week for a specific date using the concept of odd days as background academic context rather than a clinical decision trigger.
This question tests general intelligence, specifically logical reasoning and quantitative aptitude, which are components of nursing entrance examinations.
While not a clinical skill, the ability to perform systematic, multi-step calculations demonstrates attention to detail and problem-solving abilities, which are crucial for nurses in tasks like medication dosage calculation and interpreting patient data.
What if the question asked for January 1, 2100? The year 2100 is not a leap year (divisible by 100 but not by 400). This would change the leap year count and alter the final calculation, highlighting the importance of correctly applying calendar rules.
How to Approach the Question
First, identify that this is a calendar problem that requires calculating the day of the week.
Recall the concept of 'odd days,' which are the number of days remaining after dividing the total number of days by 7.
Break down the time period before the target date (i.e., up to December 31, 1999) into manageable chunks: centuries and remaining years.
Calculate the odd days for each chunk: 1600 years have 0 odd days; the next 300 years (1601-1900) have 1 odd day.
For the remaining 99 years (1901-1999), calculate the number of leap years (99/4 = 24) and ordinary years (99-24 = 75). Then find the total odd days: (24 * 2) + (75 * 1) = 123 days, which is 4 odd days (123 mod 7).
Sum the odd days from all chunks (0 + 1 + 4 = 5) to find the day for December 31, 1999. A value of 5 corresponds to Friday.
Concept Tested & Keywords
Concept Tested: Calculating the day of the week for a specific date using the concept of odd days.
Stem keywords: day of the week, 1st January 2000
Lead-in keywords: What
Question ID
Q2Gd4ZLSGMSwLRNJ5y6-QX
Practise the full Daman & Diu Staff Nurse - 2018
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