DSSSB - 28 August 2019 (Shift-1)
Non Nursing Subjects
Hard

What is the largest 4-digit number that is divisible by 20, 50, 60, and 80?

Appeared in: DSSSB - 28 August 2019 (Shift-1)

Explanation

  • The problem requires finding the largest 4-digit number that is a common multiple of 20, 50, 60, and 80.
  • First, calculate the Least Common Multiple (LCM) of these numbers. The prime factorization is: 20=2²×5, 50=2×5², 60=2²×3×5, 80=2⁴×5. The LCM is 2⁴×3¹×5² = 16×3×25 = 1200.
  • The required number must be a multiple of the LCM, 1200.
  • The largest 4-digit number is 9999. To find the largest multiple of 1200 within this range, divide 9999 by 1200, which gives 8.33.
  • Taking the integer part (8) and multiplying it by the LCM gives the answer: 1200 × 8 = 9600.

Why Other Options Were Wrong

  • Option B: Although 9000 is a large 4-digit number and divisible by 20, 50, and 60, it is not divisible by 80 (9000 / 80 = 112.5).
  • Option C: 9240 is not divisible by 50 (a number divisible by 50 must end in 00 or 50) or 80.
  • Option D: 9480 is not divisible by 50.

Related Visual

Visual explanation — Related Visual
Clinical Relevance
  • Nursing practice connection: This is primarily an exam-oriented knowledge point with limited direct bedside application, so retain Least Common Multiple (LCM) and Divisibility as background academic context rather than a clinical decision trigger.
  • This question tests basic arithmetic and logical reasoning, which are essential skills for nurses.
  • Nurses frequently perform calculations for medication dosages, IV drip rates, and fluid balances, where accuracy is critical for patient safety. Strong numeracy skills are a foundational requirement.
  • What if the question asked for the smallest 5-digit number divisible by these numbers? In that case, after finding the LCM (1200), you would find the smallest multiple of 1200 that is greater than 9999. 1200 × 9 = 10800.
How to Approach the Question
  • First, read the question carefully to understand that you need to find a number that is a common multiple of 20, 50, 60, and 80.
  • Recognize that the most efficient way to solve this is by finding the Least Common Multiple (LCM) of the given divisors.
  • Calculate the LCM using a method like prime factorization. This gives you the smallest number that all the given numbers can divide into.
  • Identify the range you are working with, which is the set of 4-digit numbers (1000 to 9999).
  • Divide the largest number in the range (9999) by the LCM (1200) and take the integer part of the result.
  • Multiply this integer by the LCM to get the largest multiple within the desired range. This is your answer.
Concept Tested & Keywords
  • Concept Tested: Least Common Multiple (LCM) and Divisibility
  • Stem keywords: largest 4-digit number, divisible by, 20, 50, 60, 80
  • Lead-in keywords: What is

Question ID

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