UP NHM CHO 7 Sept 2022 (Shift-2)
Non Nursing Subjects
Hard

Pipe A and Pipe B can fill an empty tank in 45 minutes and 63 minutes respectively, while Pipe C can empty a full tank in 54 minutes. When the tank was empty, initially both inlet pipes (A and B) were opened. After some time, Pipe B was closed and at the same time Pipe C was opened. The tank was filled completely in a total of 75 minutes from the start. For how many minutes was Pipe B kept open?

Appeared in: UP NHM CHO 7 Sept 2022 (Shift-2)

Explanation

  • The problem requires calculating the duration a specific pipe was open in a multi-stage filling and emptying process.
  • The solution involves finding a common unit of work (total capacity) by calculating the LCM of the individual times.
  • Efficiencies (work rate per minute) are calculated for each pipe; filling pipes have positive rates, and emptying pipes have negative rates.
  • An equation is formed by summing the work done by each pipe over its respective operational time, equating the total to the tank's capacity.
  • Solving the linear equation for the unknown time 't' gives the duration Pipe B was open.

Why Other Options Were Wrong

  • Option B: This value is incorrect. If Pipe B were open for 20 minutes, the total volume filled would be 525 + (65 * 20) = 525 + 1300 = 1825 units, which is less than the required 1890 units. This likely results from a minor calculation error.
  • Option C: This value is incorrect. If Pipe B were open for 22 minutes, the total volume filled would be 525 + (65 * 22) = 525 + 1430 = 1955 units, which is more than the tank's capacity of 1890 units.
  • Option D: This value is significantly incorrect. If Pipe B were open for 16 minutes, the total volume filled would be 525 + (65 * 16) = 525 + 1040 = 1565 units, which is far short of the required 1890 units.

Related Visual

Visual explanation — Related Visual
Clinical Relevance
  • Nursing practice connection: This is primarily an exam-oriented knowledge point with limited direct bedside application, so retain Work and Time: Pipes and Cisterns as background academic context rather than a clinical decision trigger.
  • This question tests quantitative aptitude, specifically the ability to solve problems related to work and time.
  • While not directly a clinical skill, strong analytical and problem-solving abilities are crucial for nurses in various aspects of their job, including medication dosage calculations, managing fluid balances, and interpreting patient data.
  • This type of logical reasoning is a component of many nursing entrance and competitive examinations in India.
How to Approach the Question
  • First, identify the rates of work for each pipe. Note that filling pipes have a positive rate and emptying pipes have a negative rate.
  • To simplify calculations, find a common 'total work' unit by calculating the Least Common Multiple (LCM) of the given time periods. This represents the tank's capacity.
  • Calculate the efficiency (work per minute) for each pipe by dividing the total capacity by the time each pipe takes.
  • Define a variable (e.g., 't') for the unknown quantity, which is the time Pipe B was open.
  • Construct an equation representing the total work done. Sum the work of each pipe (efficiency multiplied by its operating time). The total must equal the tank's capacity.
  • Solve the algebraic equation for 't' to find the answer.
Concept Tested & Keywords
  • Concept Tested: Work and Time: Pipes and Cisterns
  • Stem keywords: Pipe A, Pipe B, Pipe C, fill, empty, tank, minutes
  • Lead-in keywords: how many minutes

Question ID

Q6AFAK5VQHauq5yQr7X3Cs

Practise the full UP NHM CHO 7 Sept 2022 (Shift-2)

Attempt every question from this paper in a timed mock, then review the full solution for each one.

More Mathematics Questions

More UP NHM CHO 7 Sept 2022 (Shift-2) Questions