IGNOU Post B. SC. Nursing entrance -2021
Pharmacology
Hard

How much salt must be added in one litre of water to make a solution of normal saline (0.9%)?

Appeared in: IGNOU Post B. SC. Nursing entrance -2021

Explanation

  • The term '0.9%' w/v (weight by volume) signifies that there are 0.9 grams of solute for every 100 mL of the solution.
  • The question requires preparing 1 litre of solution, which is equivalent to 1000 mL.
  • To find the amount of salt needed for 1000 mL, a simple proportion is used: (0.9 g / 100 mL) = (x g / 1000 mL).
  • Solving for x gives 9 grams. (0.9 g * 10 = 9 g).

Why Other Options Were Wrong

  • Option A: 19 gm is an arbitrary value and does not correspond to the calculation for a 0.9% solution.
  • Option B: 90 gm would create a 9% solution in 1 litre, which is a highly concentrated hypertonic solution and would be dangerous for most clinical uses.
  • Option C: 9 gm is the correct amount of salt for 100 mL of normal saline, not for 1 litre (1000 mL).

Related Visual

Visual explanation — Related Visual
Clinical Relevance
  • Nursing practice connection: This is primarily an exam-oriented knowledge point with limited direct bedside application, so retain Drug Calculation: Percentage Solutions as background academic context rather than a clinical decision trigger.
  • Accurate drug and solution calculation is a fundamental and critical nursing skill to ensure patient safety and prevent medication errors.
  • Normal saline (0.9% NaCl) is an isotonic crystalloid solution, meaning it has the same effective osmolality as body fluids. This makes it ideal for expanding extracellular fluid volume without causing major fluid shifts in cells.
  • It is commonly used for dehydration, hypovolemia, and as a flush for intravenous lines.
How to Approach the Question
  • First, identify the key components of the question: the desired concentration (0.9%) and the final volume (1 litre).
  • Recall or look up the definition of a percentage solution in a medical context: 'X%' means 'X grams per 100 mL'.
  • Convert all units to be consistent. In this case, convert 1 litre to 1000 mL.
  • Set up a ratio or proportion to solve for the unknown amount of salt. If 0.9 g is in 100 mL, how many grams (x) are in 1000 mL?
  • Calculate the final answer: x = (0.9 g / 100 mL) * 1000 mL.
  • Compare your calculated answer (9 g) with the given options to select the correct one.
Concept Tested & Keywords
  • Concept Tested: Drug Calculation: Percentage Solutions
  • Stem keywords: salt, one litre, normal saline, 0.9%
  • Lead-in keywords: How much

Question ID

Q6OFCMpPZCXbZHpvDvnc7s

Reference Book

E6 Pharmacology Nursing Lilley 11e Part 2 p. 161-163

E6 Nursing Brunner Adult Health 3SA Vol 1 Part 1 p. 142-144

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